F(x)=3(1.06^x)+2

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Solution for F(x)=3(1.06^x)+2 equation: 



(F)=3(1.06^F)+2

We move all terms to the left:

(F)-(3(1.06^F)+2)=0



We calculate terms in parentheses: -(3(1.06^F)+2), so:

3(1.06^F)+2

We multiply parentheses

3F+2

Back to the equation:

-(3F+2)



We get rid of parentheses

F-3F-2=0

We add all the numbers together, and all the variables

-2F-2=0

We move all terms containing F to the left, all other terms to the right

-2F=2

F=2/-2

F=-1

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